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May
9th

Pic, Atmel, 8051 Çeşitli Mikrodenetleyici Devreleri

cestli.JPG

Pic, atmel, 8051, motorolara gibi hemen hemen bütün mikrodenetleyici çeşitleri ile yapılmış projelere aşağıdan ulaşabilirsiniz.

Proje listesi:


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5 Responses to “Pic, Atmel, 8051 ÇeÅŸitli Mikrodenetleyici Devreleri”

  1. By kaci on Tem 15, 2008 | Reply

    hi,
    i need some help for progamming pic 18f 458 (adc,clr ,quartz),
    thanks

  2. By admin on Tem 15, 2008 | Reply

    what kind of help

  3. By kaci on Tem 22, 2008 | Reply

    yes,i work with the compilateur ccs

    1.i want the pic18f458 opperates at 40 MHz.what i have to do.

    2.i have 3 analog input (3phase)(3 sinusoide)(ampli 2.5v),

    the adc conversion will be 10bit (5volt;correspond;1024) or

    8bit(5volt;correspond;256)

    what’s the manner to program this

  4. By Binu on Tem 25, 2008 | Reply

    Good collection of projects.

  5. By kaci on Eyl 2, 2008 | Reply

    hi all,
    in need some hope(oriontatin) in my application.
    my application consist in;
    i have 3 analog input (3 sinusoidal tensions),then i neeed a/d converter
    an0,an1,an3 (10bit conversion) and the 3 result of conversion will be used in calcul(var =fonction(read(1),read(2),read(3…) fonction is(arctan..) )
    i use the pic 18f458(with picc compiler) and i want to obtain a hightspeed intern (40MHZ)
    ,for this i have used 10MHZ with pll enabled

    my progam;
    #include
    #device adc=10
    #fuses hs, NOWDT, NOPROTECT, PUT, BROWNOUT, NOLVP
    #use delay (clock=40000000)
    double result;
    float v1,v2,v3;

    void main(void)
    {
    ld:
    setup_adc_ports(ALL_ANALOG);
    setup_adc(ADC_CLOCK_DIV_32); // utilisation de l’horloge interne pour l’ADC
    set_adc_channel(0); // Lecture sur le canal 0 du port
    result=(double)(read_adc());
    v1 = ( 5.0 * result ) / 1024;
    set_adc_channel(1); // Lecture sur le canal 1 du portA
    delay_us(10);
    result=(double)(read_adc());
    v2 = (5.01 * result) / 1024;
    delay_us(10);
    result=(double)(read_adc());
    v3 = (5.01 * result) / 1024;
    goto ld;
    }

    my questions;
    1.how much time to the ad convertion (convert 3analog input to digital)
    2.what is the faster a/d convertion 8bit or 10bit.and how much for difference.
    3.what the declaration can i use to obtain max internal execution speed (40Mhz)(i use 10MHZ with pll enabled)
    (1).#fuses hs, NOWDT, NOPROTECT, PUT, BROWNOUT, NOLVP
    #use delay (clock=40000000)

    or:
    (2).#fuses hs, NOWDT, NOPROTECT, PUT, BROWNOUT, NOLVP
    #use delay (clock=10000000)
    4.is it necessary to do delay time; (delay_us(10);)

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